
Yefim S. answered 08/10/20
Math Tutor with Experience
Let do right Riemann sum: Δx = (5 - 0)/10 = 0.5; R10 = ∑1101/(0.5i + 8)·0.5 = 0.4737.
Then we evaluate left rieman sum: L10 = ∑09[1/(0.5i + 8)·0.5 = 0.4977
We consider f(x) = 1/(x + 8) because if function f(x) = 1/x + 8 left Riemann sum DNE for interval [0, 5].
For calculation I used TI-84 sum(seq) command from List menu