Tom K. answered 07/30/20
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f(-3) = 0. We are integrating from -3 to -3.
f'(-3) = 3^√((-3)^2-1) = 3^√8 = 3^2√2
Nicole L.
asked 07/29/20let f(x)=∫-3 to x 3^√t^2-1 dt
find f(-3) and f'(-3)
Tom K. answered 07/30/20
Knowledgeable and Friendly Math and Statistics Tutor
f(-3) = 0. We are integrating from -3 to -3.
f'(-3) = 3^√((-3)^2-1) = 3^√8 = 3^2√2
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