Yefim S. answered 07/28/20
Math Tutor with Experience
Surface area A = 2π∫08x(t)√(x'2(t) + y'2(t))dt = 2π∫08[(et - t)√(et - 1)2 + (2et/2)2]dt = 2π ∫08(et - t)(et + 1)dt =
2π∫08(e2t - tet + et - t)dt = 2π(1/2e2t + 2et - 1/2t2 - tet)08 = 2π[(1/2e16 + 2e8 -1/2·64 - 8e8) - (1/2 + 2)] = 8850318.025π = 27803943.29