Yefim S. answered 07/27/20
Math Tutor with Experience
Δg(x,y,z) ≈ dg(x,y,z) = ∂g/∂x·Δx + ∂g/∂y·Δy + ∂g/∂z·Δz = (1 + cosz)Δx + (1 - sinz)Δy + (- xsinz - ycosz)Δz
Partial derivatives we avoluate at point P0(2, - 1, 0). So Δg(x, y, z) ≈ 2Δx + Δy + Δz.
Vector P0P1 = (- 2, 2, 2). AbsP0P1 = 2√3. And because P0P = P0P1·0.3/(2√3) = (-1,1,1)·0.3/√3 =
= (- √3/10, √3/10, √3/10).
So Δx = - √3/10, Δy = √3/3 and Δz = √3/3 and Δg ≈ 2(- √3/10) + √3/10 + √3/10 = 0