
Sam Z. answered 07/25/20
Math/Science Tutor
I=∫ln(1+x)dx
0
I=x ln(1+x)−∫dx+∫1/(1+x)dx =2.0273integral
.5 =0 differential
Helayna I.
asked 07/25/201.)
a-Evaluate the integral from 0 to 1/2 of ln(1+x)dx with an accuracy of 10^-4 using techniques of integration and a calculator.
b- Now approximate the integral from 0 to 1/2 of ln(1+x)dx to an accuracy of 10^-4 using the Maclaurin series of ln(1+x) and term-by-term integration. You will have to figure out how many terms of the series must be used. Are the answers to a) and b) very similar numbers?
Sam Z. answered 07/25/20
Math/Science Tutor
I=∫ln(1+x)dx
0
I=x ln(1+x)−∫dx+∫1/(1+x)dx =2.0273integral
.5 =0 differential
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