
Patrick B. answered 07/24/20
Math and computer tutor/teacher
integrating:
f'(x) = -2x + 6x^2 - 4x^3 + C
f'(0) = 12 ---> C = 12
so f'(x) = -4x^2 + 6x^2 -2x + 12
integrating again:
f(x) = -(4/3)x^3 + 2x^3 - x^2 + 12x + C
f(0) = 5 ---> C = 5
f(x) = -(4/3)x^3 + 2x^3 - x^2 + 12x + 5