The derivative of tan is sec2.
Put y = 2θ and dy = 2 dθ
∫sec2(2θ) dθ = ∫sec2y (1/2) dy = (1/2) tan y + C = (1/2) tan 2θ + C
Mashal A.
asked 07/21/20∫ sec^2(2𝜃) 𝑑𝜃 Evaluate each integral
The derivative of tan is sec2.
Put y = 2θ and dy = 2 dθ
∫sec2(2θ) dθ = ∫sec2y (1/2) dy = (1/2) tan y + C = (1/2) tan 2θ + C
William W. answered 07/21/20
Experienced Tutor and Retired Engineer
Let u = 2θ
Then du/dθ = 2 or, rearranging, dθ = du/2
Using ∫sec2(2θ) dθ use the substitution above to re-write the integral:
∫sec2(u) du/2 or, bringing the 1/2 out in front: 1/2∫sec2(u) du
Since the derivative of tan(u) = sec2(u), then the antiderivative of sec2(u) is tan(u) so the integral becomes:
1/2 tan(u) + C
Now, replace the u with 2θ making the final answer:
1/2 tan(2θ) + C
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