
Mark M. answered 07/19/20
Mathematics Teacher - NCLB Highly Qualified
√(ab) = (√a)(√b)
√(-b) = (√-1)(√b)
√(-b) = i (√b)
Lily S.
asked 07/19/20aka i2=-1.
i know i is an imaginary number, and if the number inside the square root is negative then the result is an imaginary number.
Mark M. answered 07/19/20
Mathematics Teacher - NCLB Highly Qualified
√(ab) = (√a)(√b)
√(-b) = (√-1)(√b)
√(-b) = i (√b)
Richard P. answered 07/19/20
PhD in Physics with 10+ years tutoring experience in STEM subjects
A little bit of insight is that the roots of any polynomial function with real coefficients , that is roots of
f(x) = 0 where f is polynomial of any degree with real coefficients are in the from:
a + b i ( in other words a general complex number) with a and b being real numbers.
This is important because it means that while i is involved, that is the end of it. Nothing more complicated is needed.
for example sqrt( i ) = ..707 + .707 i
.707 is actually sqrt(2) /2
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