Yefim S. answered 07/13/20
Math Tutor with Experience
Lenar approximation at x = 0 L(x) = f(0) + f'(0)x; f(0) = sqrt(4 - 0) = 2; f'(x) = - 1/2(4 - x)-1/2; f'(0) = -1/2·1/2 =
- 1/4. L(x) = 2 - 1/4x We say (4 - x)1/2 ≈ 2 - 1/4x.
If x = 0.1 we get 3.91/2 ≈ 2 - 1/4·0.1 = 1.975
If x = 0.01 we get 3.991/2 ≈ 2 - 1/4·0.01 = 1.9975
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