Mark M. answered 07/08/20
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = x2 / (3 - 5x) = (x2/3) / (1 - 5x/3) = a / (1 - r)
f(x) = ∑(from 0 to ∞) arn = ∑(from 0 to ∞) (x2/3)(5x/3)n = (1/3)∑(from 0 to ∞) [(5/3)nxn+2]
The series converges as long as -1 < r < 1. That is, when -1 < 5x/3 < 1.
So, -3/5 < x < 3/5. Radius of convergence = half the length of the interval of convergence = 3/5.