Arturo O. answered 07/07/20
Experienced Physics Teacher for Physics Tutoring
The Maclaurin series is a Taylor series expanded about x=0.
f(x) = f(0)(x - 0)0/0! + f'(0)(x - 0)1/1! + f''(0)(x - 0)2/2! + ....
Terms with f''' and higher derivatives are zero, so
f(x) = f(0)x0/0! + f'(0)x1/1! + f''(0)x2/2!
f(0) = 1
f'(0) = (6x + 2)|0 = 2
f''(0) = 6
f(x) = 1(1)/1 + 2x/1 + 6x2/2 = 1 + 2x + 3x2
The Maclaurin series just returns the exact same polynomial.