Nitin P. answered 07/06/20
Machine Learning Engineer - UC Berkeley CS+Math Grad
Take the logarithm of both sides to get:
ln y = cos(3x)ln(ln(3x))
Taking the derivative of both sides, we have:
y'/y = -3sin(3x)ln(ln(3x)) + cos(3x)/xln(3x)
Therefore, since y = (ln(x))cos(3x), we have:
y' = y(cos(3x)/xln(3x) - 3sin(3x)ln(ln(3x))) = (ln(x))cos(3x)(cos(3x)/xln(3x) - 3sin(3x)ln(ln(3x)))