
Nitin P. answered 07/06/20
Machine Learning Engineer - UC Berkeley CS+Math Grad
Taking the logarithm of both sides, we have:
ln y = 7ln(tan x)/x
Taking the derivative of both sides, we have:
y'/y = 7(-ln(tan(x))/x2 + sec2x/(x tan x))
Since y = (tan(x))7/x, we have:
y' = 7y(sec2x/(x tan x) - ln(tan(x))/x2) = 7(tan(x))7/x(sec2x/(x tan x) - ln(tan(x))/x2)