how do you solve 3x^2+12x+36=-66

Question

the original question is not this but i have gotten this far and need help ending it.  please help

Answer 1

3x²+12x+36 = -66

 

First we want to set the equation equal to zero.  To do this, we add 66 on both sides of equation.

 

3x²+6x+102 = 0

 

Next we factor.  3, 6, and 102 are all multiples of 3 so we can use a GCF of 3.

 

3(x²+2x+34)=0

 

Next, use the quadratic formula

 

x = (-b±sqrt(-b²-4ac))/(2a)

 

where a=1 , b=2 , c=34