Jon S. answered 06/26/20
Patient and Knowledgeable Math and English Tutor
This places the angle x in the 2nd quadrant, where cosine is negative, sine is positive.
We can form a right triangle in the 2nd quadrant with leg length 2 (horizontally) and length length 3 (vertically), so that the hypotenuse = SQRT(13).
The cosine x = -2/SQRT(13)
The sine x = 3/SQRT(13)
The cosecant x = 1/sine = SQRT(13)/3
The tangent x = -3/2