Calculus 2 evaluating integrals (section 7.2#7)

Question

Evaluate the integral:tan2(x)cos3(x)dx (Please show detailed work, box answer.)

Answer 1

∫tan²xcos³xdx = ∫(sin²x / cos²x)cos³xdx = ∫sin²x cosxdx

Let u = sinx. Then du = cosxdx.

So, the integral can be rewritten as ∫u²du = (1/3)u³ + C = (1/3)sin³x + C

Answer 2

With no values there's nothing to work with.