Edward C. answered 06/23/20
Caltech Grad for math tutoring: Algebra through Calculus
Hey Ryan,
Use the hint to rewrite the integral as ∫1dt - ∫[6/(t+6)]dt .
You can make the substitution u = t+ 6 to do the second integral.
Ryan G.
asked 06/23/20Find the indefinite integral.Hint : t/t+6 = 1 − 6/t+6 (Use C for the constant of integration. Remember to use absolute values where appropriate.)
∫t/t+6dt
Edward C. answered 06/23/20
Caltech Grad for math tutoring: Algebra through Calculus
Hey Ryan,
Use the hint to rewrite the integral as ∫1dt - ∫[6/(t+6)]dt .
You can make the substitution u = t+ 6 to do the second integral.
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