Albert L. answered 06/17/20
WashU Tutor for intro to CompSci, SAT Math/English, Algebra
h(x) = x cos(6/x)
Apply Product Rule (f(x) * g(x) where x is f(x) and cos(6/x) is g(x)):
Reminder of Product Rule: (f(x)g(x))' = f(x) * g(x)' + g(x) * f(x)'
h(x)' = x * cos(6/x)' + cos(6/x) * x'
Solving [cos(6/x) * x']: x' = 1,
cos(6/x)*1 = cos(6/x)
Solving [x * cos(6/x)']:
Apply Chain Rule
Chain Rule Reminder: f(g(x))' = g(x)' * f'(g(x)) (where f(x) is cos(x) and g(x) is 6/x)
(6/x)' = -6/x^2 (power rule of -1)
cos(x)' = -sin(x)
x * cos(6/x) = 6/x^2(sin(6/x)) (negatives cancel out from -sin(x) and -6/x^2)
Final Solution: h(x)' = 6(sin(6/x))/x^2 + cos(6/x)