
William W. answered 06/16/20
Experienced Tutor and Retired Engineer
I'm unsure if the first equation is f(x) = αcos(x) + 2 or f(x) = αcos(x + 2). I'll assume the first.
You want to find values of α and β where the two functions have the same function value at x = 0 (the function is then continuous) and they also have the same slope at x = 0 (the function then has no sharp points). You will get two equations in two unknowns and will be able to then solve the system of equations.
1) Set αcos(x) + 2 equal to βe3x + αx2 and make x = 0 making the equation α + 2 = β
2) Take the derivatives and set them equal. Then solve the system to get α and β.
To double check your answers, plot the two functions and look at x = 0 to make sure it is a continuous and smooth transition.


William W.
I do not believe that beta = 0 is a "trivial" solution. Consider y = αcos(x) + 2. This is a function that will always, no matter what the value of alpha, have a maximum at x = 0, meaning the slope is 0 at x = 0. The only way to alter a cosine function from having this characteristic is to add a phase shift (move it horizontally). That means we MUST find an alpha and beta for y = βe^3x + αx^2 such that the resulting graph has a slope of zero at x = 0. Since the derivative of αx^2 = 2αx, at x = 0 that portion of the derivative will be zero, leaving the issue to find how the derivative of y = βe^3x can be zero at x = 0. For y = βe^3x, y' = 3βe^3x and the ONLY way that can be zero is if β = 0.06/20/20
Shailesh K.
06/19/20