Patrick B. answered 06/12/20
Math and computer tutor/teacher
f(x) = −0.1x^2 − 0.2x + 22
df/dx = f'(x) = -0.2x - 0.2
f ' (x) = -0.2 ( 12000 ) - 0.2 = -2 (12000)/10 - 0.2
= -24000/10 - 0.2
= -2400 - 0.2
= -2400.2
Gabrielle D.
asked 06/12/20where x is the quantity demanded in thousands and p is the unit price in dollars.
(a) Find f'(x).
(b) What is the rate of change of the unit price (in dollars per 1,000 lamps) when the quantity demanded is 12,000 units (x = 12)?
Patrick B. answered 06/12/20
Math and computer tutor/teacher
df/dx = f'(x) = -0.2x - 0.2
f ' (x) = -0.2 ( 12000 ) - 0.2 = -2 (12000)/10 - 0.2
= -24000/10 - 0.2
= -2400 - 0.2
= -2400.2
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