
Ron H. answered 06/16/20
Veterinary Student w/ 20 Years Experience
*I assume there is a type and the cost of 30 lb of rice and 12 lb of potatoes cost $20.40 as this allows you to solve the set of equations.*
R = Price of Rice
P = Price of Potatoes
R(20) + P(10) = 14.20
R(30) + P(12) = 20.40
Multiply the both sides of the top equation by (-3) and both sides of bottom equation by 2:
R(-60) + P(-30) = -42.60
R(60) + P(24) = 40.80
Add the two equations, R will cancel out and you can solve for P:
P(-6) = -1.8 ----> Divide both sides by -6
P = $0.30
Plug this value into either of the equations and solve for R:
R(20) + 0.3(10) = 14.20
R(20) + 3.00 = 14.20
R(20) = 11.20
R = $0.56
Double check your work by putting both R and P into each equation and checking to see if they still are true:
0.56(20) + 0.30(10) = 14.20 ---> TRUE
0.56(30) + 0.30(12) = 20.40 ---> TRUE
Finally, enter these values into the question:
R(10) + P(50) =
0.56(10) + 0.30(50) = $20.60
$20.60 is the solution