
Patrick B. answered 06/09/20
Math and computer tutor/teacher
ln y = ln e^x + ln cos x - ln arctanx - 5ln 4ln(3x^4)
y'/y = 1/e^x + sinx/cosx - 1/(1+x^2) - 5 ( 12x^3/ ln 4ln 3x^4))
y' = [ 1/e^x + sinx/cosx - 1/(1+x^2) - 5 ( 12x^3/ ln 4ln 3x^4))] y
where y is the given function