
Jocelyn C. answered 06/05/20
Calculus (I-III) Tutor with 8 Years of Teaching Experience
Hi Gabrielle,
First, to expand f(a + h), we need to substitute (a+h) and into f(x) wherever x appears.
f(a+h) = 4(a+h)3 - (a+h)2 + 1
Now to expand (you can FOIL this in two steps):
f(a+h) = 4(a3+ h3 + 3a2h + 3ah2) - (a2 + 2ah + h2) + 1
f(a+h) = 4a3 + 4h3 + 12a2h + 12ah2 - a2 - 2ah - h2 + 1
Then, to expand f(a)/h, we will first substitute a into f(x) wherever x appears.
f(a) = 4a3 - a2 + 1
Note here I've assumed that we're solving for (f(a+h) - f(a))/h; let me know if this isn't the case.
We solve for the above quantity by substituting the two terms above:
f(a+h) - f(a) =
4a3 + 4h3 + 12a2h + 12ah2 - a2 - 2ah - h2 + 1 - (4a3 - a2 + 1)
= 4a3 + 4h3 + 12a2h + 12ah2 - a2 - 2ah - h2 + 1 - 4a3 + a2 - 1
= 4h3 + 12a2h + 12ah2 - 2ah - h2
Finally, we divide this all by h:
(f(a+h) - f(a))/h =
(4h3 + 12a2h + 12ah2 - 2ah - h2)/ h
= 4h2 + 12a2 + 12ah - 2a - h
And this is the final, simplified result.
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