Please I need help

Question

Suppose that at a busy traffic junction, the probability p of an individual car having an accident is 0.0001.During a certain part of the day, 100 cars pass through the junction. What is the probability of two or more cars being involved in an accident within this period?

Answer 1

The author of the problem may have intended for one to use the binomial distribution, but this assumes independence, which does not make sense here. If there is an accident at an intersection, it is very likely that at least two cars were involved.

Under the assumption of independence, P(2 or more cars in an accident) = 1 - P(0 or 1 cars in an accident) =

1 - binom.dist(1,100,.0001,1) = 0.0000491777733619969, approximately 4.9178 * 10^-5

If one thinks that, if one car is in an accident, it's likely that 2 were, P(2 cars in an accident) approaches .005.

Answer 2