
Patrick B. answered 05/31/20
Math and computer tutor/teacher
How much does it cost to enter the contest and play the game?
Is there a "blind bet" where the customer must put some money down?
Let N be the price to play....
0.25 (1-N) + 0.1*(10-N) + 0.04(20-N) + 0.01(50-N) + 0.6(0-N) =
0.25 - 0.25N + 1 - 0.1N + 0.8 - 0.04N + 0.5 - 0.01N - 0.6N =
2.25 - N
So the expected value is Exp(n) = 2.25-n where n is the price to play