Write the equation in logarithmic form.

Question

Answer 1

b^c=x

Writing in a logarithmic expression:

log_bx=c

For your problem 3^-2=1/9

The logarithmic expression is

log₃(1/9)=-2

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Answer 2

Hi Xavier. The logarithmic form of 3, to the negative 2 power, = 1/9 is log (lower case 3) 1/9 = -2.

What you need to remember is to put log first, followed by the base number (3) in lower case form. Follow this with your answer in exponent format (1/9). Then set that = to the exponent that you were given (-2).

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Answer 3

b^x = y

log_x y = x

The base in log is the same as the base from the exponential function. Logarithm is the inverse function for exponential function. Swap in up and output.

log₃ 1/9 = -2