What is the direction of this vector as a bearing and in polar form. (-2,3)

Question

What is the direction of this vector as a bearing and in polar form. (-2,3)

Answer 1

Cartesian Vector Form Is <X,Y>

Polar Vector Form is <r,theta>

Note the transform equations

x=rcos(theta)

y=rsin(theta)

r = mag V = [x^2 +y^2 ]^.5

theta = arctan(y/x)

Given <-2,3>

r = [ 4+9]^.5 = 13^1/2

theta = arctan(3/-2) = -56.31 degrees from + x axis ClockWise

or theta = 303.69 degrees from + x axis Counter Clock wise

Polar Vector Form V = <13^1/2 , -56.31 >

Heading -56.31 degrees from +x axis clockwise

LIKE and FEEL FREE to ask me

Answer 2

Draw and label a diagram with the vector on a Cartesian plane.

arctan 3 / -2 = β

35.78º ≈ β

Bearing equals β + 270°

Radius equals magnitude of vector

Can you complete and answer?