We start with the factored form of a polynomial with roots x = -1, x = 1, and x = 6. That is, we have
(x+1)(x-1)(x-6).
However, we can see that this expands easily so that we have
(x+1)(x-1)(x-6)=(x2-1)(x-6)=x3-6x2-x+6.
Since the coefficient of x3 is 1, we have that this is the correct order-three polynomial (or, rather, cubic).
Notice that if the polynomial if the equation had required a coefficient of x3 different from 1, we could have simply scaled the whole polynomial by that value since this would not change the roots of the polynomial.
Hope that helps!