∫(X^2sin(x))/(1+x^6)

Question

upper bound pi/2

lower upper -pi/2

Answer 1

If f(-x) = -f(x), then f(x) is an odd function.

For f(x) = x²sinx / (1 + x⁶), the function is odd since sin(-x) = -sinx.

For odd functions, ∫_{(from -a to a)} f(x) dx = 0

So, the value of the given integral is 0.