write the equation of a line that is parallel to y=-1/2x-4 and that passes through the point (9,-6)

Answer 1

Ok, so to ensure that the line is parallel to y=-1/2x -4 the gradient of your new line must be the same so in this example the gradient of your new line is -1/2

So your new equation starts to look like this...

y=-1/2x + B

Since the line needs to pass through point (9,-6) that means you need to make x = 9 and y = -6.

Substitute these into y=-1/2x + B and it will allow you to solve for B

-6 = -1/2(9) + B

-6 = 4.5 + B

-6--4.5 = B

-1.5 = B

B= -1.5

so the new equation becomes y=-1/2x- 1.5

You can test this by substituting x=9 into the equation and making sure you get y = -6:

y=-1/2x - 1.5

y=-1/2(9) - 1.5

y= -4.5-1.5

y=-6 - Great it worked!

Answer 2

y=-1/2x-4

Slope m is -1/2

(9, -6) is your (x1, y1)

Use point slope form y - y1 = m (x - x1) to find the equation in point slope form y = mx + b.