do you know the equation of a line that is parallel to y=-5/4x+7 and passes through the point (-4,1)?

Answer 1

Ok, so to ensure that the line is parallel to y=-5/4x + 7 the gradient of your new line must be the same so in this example the gradient of your new line is -5/4

So your new equation starts to look like this...

y=-5/4x + B

Since the line needs to pass through point (-4,1) that means you need to make x = -4 and y = 1.

Substitute these into y=-5/4x + B and it will allow you to solve for B

1 = -5/4(-4) + B

1 = 5 + B

1-5 = B

-4 = B

B=-4

so the new equation becomes y=-5/4x- 4

You can test this by substituting x=-4 into the equation and making sure you get y = 1:

y=-5/4x - 4

y=-5/4(-4) - 4

y= 5 -4

y=1 - Great it worked!

Answer 2

1 = (-5/4)x + b

1 = (-5/4)(-4) + b

1 = 5 + b

-4 = b

Equation:

y = (-5/4)x - 4

Answer 3

The given line has slope -5/4 and parallel lines have the same slope.

So, an equation of the line with slope -5/4 and which passes through the point (-4,1) is:

y - 1 = (-5/4)[x - (-4)]

So, y = (-5/4)x - 4

Answer 4

Lola:

A line that is parallel to y=(-5/4)x+7 will have the same slope, -5/4.

Write the equation of the line of the form y-y_a = m*(x-x_a) where m is the slope.

Hope this helps!