Christopher J. answered 05/23/20
Tutor
New to Wyzant
Berkeley Grad Math Tutor (algebra to calculus)
Deonna:
Use the product and chain rule.
f '(s) = d/ds(s9+1)*e-s^9 + (s^9+1)*d/ds(e-s^9)
Hint d/ds(e-s^9) = -9s8*e-s^9
Christopher J.
Deonna: f'(s) = (9s^8)*e^(-s^9) -9s^8*e^(-s^9)*(s^9+1)05/23/20