
Nitin P. answered 05/22/20
Machine Learning Engineer - UC Berkeley CS+Math Grad
To find the normal line, we must first find the tangent slope, then take its negative reciprocal. Taking the derivative, we have:
f'(π) = sec2(π) = 1
Since the tangent slope is 1, the normal slope is therefore -1. Now, we need to find f(π), which is:
f(π) = tan(π) = 0
Now, we use the point-slope form y = m(x - a) + b for a line with slope m passing through point (a,b). Our line has slope -1 and passes through (π,0), so the equation of the normal line is:
y = -(x-π) = π - x