Determine if ∑n=2 to ∞ 1/ln(n) is convergent or divergent using Comparison Test

Question

Determine if ∑n=2 to ∞ 1/ln(n) is convergent or divergent using Comparison Test

Answer 1

n > ln n for all n

1/n < 1/ln n

Therefore, the series sum of 1/ln n diverges by the comparison test.