Use the graph of f(t) = 2t + 1 on the interval [–1, 4] to write the function F(x), where f of x equals the integral from 2 to x of f of t dt.

Question

Use the graph of f(t) = 2t + 1 on the interval [–1, 4] to write the function F(x), where .

 F(x) = x² + 3x 

F(x) = 2x + 1 

F(x) = x² + x – 20 

F(x) = x² + x – 6

Answer 1

This question is not entirely clear, but

the integral from 2 to x of (2t + 1) dt = x² + x - 6.

I am unclear what the interval [-1,4] has to do with the problem.