
Christopher J. answered 05/18/20
Berkeley Grad Math Tutor (algebra to calculus)
Rachel:
f'(x) > 0 for x>5 and f'(x) < 0 for x<5. So f(x) is decreasing on x<5 and increasing on x>5. Obviously, it can't have a relative maximum at x=5.
Since f'(x) is increasing, the slope of f'(x) is always positive. The slope of f'(x) is f ''(x). So f ''(x) > 0 and f is always concave up.