How much work is required to lift a 700-kg satellite to an altitude of 1⋅106 m above the surface of the Earth?

Question

How much work is required to lift a 700-kg satellite to an altitude of 1⋅10^6 m above the surface of the Earth? The gravitational force is F=GMm/r^2, where M is the mass of the Earth, m is the mass of the satellite, and r is the distance between the satellite and the Earth's center. The radius of the Earth is 6.4⋅10^6 m, its mass is 6⋅10^24 kg, and in these units the gravitational constant,G , is 6.67⋅10^-11.

Work=_________

(include units; for this problem assume all given constants are accurate to many significant figures.)

Answer 1

I[6.4*10^6,7.4*10^6] 6.67⋅\*10^-11* 700 * 6*10^24/r^2 dr =

-6.67⋅10^-11* 700 * 6*10^24/r E[6.4*10^6,7.4*10^6] =

5915118243.24324