Amanda H.

asked • 05/15/20

Let f(x)=p+9/(x-q), for x≠q.

Let f(x)=p+9/(x-q), for x≠q. The line x=3 is a vertical asymptote to the graph of f.

The graph of f has a y-intercept at (0,4).

Write down the values of q,p and the equation of the horizontal asymptote of the graph of f.

The graph of f has a y-intercept at (0,4).

Find the value of p.


I need explanation for this question because I have problem with problems such as this one.

1 Expert Answer

By:

Paul M. answered • 05/18/20

Tutor
5.0 (39)

BS Mathematics, MD

Amanda H.

I have a question. Does it count for both parts of the question? I mean the equation for p. Also when I calculated it, I got p=7. I guess that´s incorrect looking at the p=-12. How do I get such an answer? Do I have multiply the whole equation by -3 and then what I get on the left side it the final answer for p?
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05/19/20

Paul M.

tutor
You get q=3 because at the vertical asymptote the denominator must be 0. Then you put x=0 and y=4 into the equation and solve for p, which means clear fractions first (multiply through by -3). I hope that helps. And oops, I made a typo p=-21, not -12!
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05/19/20

Amanda H.

Oh okay) thank you so much) you helped me a lot) thank you
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05/19/20

Davian L.

Can 9/-3 be simplified further into -3? So that p=7
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09/21/20

Rachel F.

p is 7. my math analysis teacher verified.
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11/23/20

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