
Mark M. answered 05/15/20
Tutor
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Mathematics Teacher - NCLB Highly Qualified
y = x + 1/x
yx = x2 + 1
0 = x2 - yx + 1
x = [y ± √(y2 - 4)] / 2
f-1(x) = [x ± √(x2 - 4)]
Kate L.
asked 05/14/20given the function f(x)=x+1/x, find its inverse f^-1(x)
Mark M. answered 05/15/20
Mathematics Teacher - NCLB Highly Qualified
y = x + 1/x
yx = x2 + 1
0 = x2 - yx + 1
x = [y ± √(y2 - 4)] / 2
f-1(x) = [x ± √(x2 - 4)]
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