DIKSHA D. answered 05/14/20
Mathematics tutor
Hare f(x) = 3-x^2 on [0, √3 ]
It is a polynomial function so it is continous on the closed interval [0, √3 ] and differentiable in (0, √3 )
Thus both condition of Lagrange's mean value theorem are satisfied
Thus there exists c belongs to (0, √3 ) such that
f'(c) = f (√3 )-f(0) ⁄ ( √3 - 0 )
-2c = - √3
c = √3 / 2
since c belongs to ( 0, √3 )
Lagrange's mean value theorem is verfied
DIKSHA D.
Hi! Greetings for the day Rachel M. Lagrange's mean value theorem guarantees the existence of such c and there can be more than one such "c" belonging to that interval Here we have to find such c s.t tangent to the curve (c,f(c)) is parallel to the line segment joining the points (a,f(a)) and (b,f(b)). I hope its helpful.Feel free to contact me.05/15/20
Fauzi A.
So whats the answer ? A, b , c or d ?02/24/21
Rachel M.
Thank you so much for your amazing help! I have a question about this problem if you have time, how do I find the x-coordinates of the point(s) guaranteed by the theorem? Thank you so much in advance and I appreciate it so much05/14/20