Fatima A.
asked • 05/12/20Calculus2 application of calculus 2 , velocity problems
An object is moving and the speed of this object after t minutes is v(t)= 1 + 4t + 3t^2
minutes per meters, how far does the object travel during 3rd minutes?
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1 Expert Answer
First of all the unit for the velocity is meters per minute,; not minute per meter. Second it is actually an easy one. Just get integral from it and plug 3 to t.
S(t) = t + 2 t^2 + t^3 +c Here c = 0 since we want to know how many meters further the object travels after 3 minutes, no matter where it is standing (initial displacement). So the answer is 3 + 2.9 + 27 = 48 meters.
Fatima A.
Thank you so much 😊☺️
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05/13/20
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Stanton D.
Question not clear. Is the net displacement of the object from t=2 to 3 minutes, or the net displacement of the object from t=0 to 3 minutes sought? In either case, the indefinite integral of the velocity with respect to t is c + t +2t^2 + t^3 . Evaluate that at the desired endpoints and take the difference of the two values!05/12/20