Area in Polar is 1/2 Integral of (cos (2x))^2 dx from 0 to pi/4. Using double angle formula we get
1/2 Integral of (cos(4x + 1))/2 dx which after calculation will be = 0,19635.
Arthur J.
asked 05/12/20What integral will give the area of the shaded region?
r=cos2θ
With half of one petal as the shaded region.
Area in Polar is 1/2 Integral of (cos (2x))^2 dx from 0 to pi/4. Using double angle formula we get
1/2 Integral of (cos(4x + 1))/2 dx which after calculation will be = 0,19635.
Christopher J. answered 05/12/20
Berkeley Grad Math Tutor (algebra to calculus)
Hi Arthur:
when is r=0: cos(2*θ)=0 means 2θ=pi/2 so θ=pi/4
Next we can use A= ∫ (1/2)*r2 dθ
r2= cos^2(2*θ)
so A=(1/2) ∫ cos^2(2*θ) dθ where the integral bounds are 0 and pi/4
remember cos^2(θ) = (1+cos(2*θ))/2 so that cos^2(2*θ) = (1+cos(4*θ))/2
This hint should give you enough to finish the problem.
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