resultant airplane velocity (facing air pressure)

Question

An airplane is heading in the direction 330 degrees when it encounters a wind from 225 degrees. find the resultant airplane velocity if the wind speed is 50 km/h and the plane speed is 430 km/h.

Answer 1

Airplane vector = 430Cos(60) = 372.4j and 430Sin(60) = -215i

Wind vector = 50Cos(-45) = -35.36i and 50Sin(-45) = -35.36j

The resultant velocity is -250.06i + 372.4j = 448.6 mph at an angle of -56.1°