Patrick B. answered 05/07/20
Math and computer tutor/teacher
integral ( f g) = integral (f) * g + f * integral (g)
f = 1 and g=x^2
integral (f) = x and integral (g) = (1/3)x^3
integral (fg) = integral(x^2) = (1/3)x^3
plugging into the equation:
(1/3)x^3 = x *x^2 + 1 * (1/3)x^3 = x^3 + (1/3)x^3 = (4/3)x^3
it is false and there is a counter example
the only value where it holds true is x=0, upon solving that equation