Mark M. answered 05/06/20
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
∫[cos(2x) / √(5 - 2sin(2x)) dx
Let u = 5 - 2sin(2x). Then, du = -4cos(2x)dx. So, cos(2x)dx = (-1/4)du
The integral can then be rewritten as (-1/4)∫ [du / √u] = -(1/2)√u + C = -(1/2)√[5 - 2sin(2x)] + C