Yefim S. answered 05/03/20
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First h(x) = ∫ from ex to 9 of ln(t)dt = - ∫from 9 to ex of lntdt;
By 1 fundamental theorem of calculus we have h'(x) = - ln(ex)·(ex)' = - x·ex;
Answer: h'(x) = - x·ex;