Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.

Question

g(x) = ∫x0 √ t^2 + t^4 dt

Answer 1

As I understand g(x) = ∫_x⁰sqrt(t² + t⁴)dt = - ∫₀^xsqrt(t² + t⁴)dt, then by 1st fundamental theorem of calculus

g'(x) = - sqrt(x² + x⁴).

Answer: g'(x) = - sqrt(x² + x⁴) = - (x² + x⁴)^1/2.