Arturo O. answered 05/01/20
Tutor
New to Wyzant
f'(x) = 1 + 3x1/2
f(x) = ∫(1 + 3x1/2)dx = x + 2x3/2 + c
f(4) = 22
4 + 2(4)3/2 + c = 22
c = 2
f(x) = x + 2x3/2 + 2
Ashley B.
asked 05/01/20Arturo O. answered 05/01/20
f'(x) = 1 + 3x1/2
f(x) = ∫(1 + 3x1/2)dx = x + 2x3/2 + c
f(4) = 22
4 + 2(4)3/2 + c = 22
c = 2
f(x) = x + 2x3/2 + 2
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