
Patrick B. answered 04/29/20
Math and computer tutor/teacher
U = t^3
dU = 3* t^2 dt
(1/3) du = t^2 dt
integral [f(t^3) * t^2 dt] , t=0....2
= (1/3) integral [ f(U) du ], U = 0...8
= 10/3
Luis A.
asked 04/29/20If f is continuous and
∫ (1 to 8) f(t) dt = 10,
find
∫ (1 to 2) t^2f(t^3) dt
Patrick B. answered 04/29/20
Math and computer tutor/teacher
U = t^3
dU = 3* t^2 dt
(1/3) du = t^2 dt
integral [f(t^3) * t^2 dt] , t=0....2
= (1/3) integral [ f(U) du ], U = 0...8
= 10/3
Mark M. answered 04/29/20
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let u = t3. Then, du = 3t2dt. So, t2dt = (1/3)du.
When t = 1, u = 13 = 1 and when t = 2, u = 23 = 8.
So, ∫(from 1 to 2) t2 f(t3) dt = (1/3)∫(from 1 to 8) f(u) du = (1/3)(10) = 10 / 3
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