Touba M. answered 05/02/20
B.S. in Pure Math with 20+ Years Teaching/Tutoring Experience
Hi Sam,
I understand your problem is f(x) = 1/(x-1) + 1/x is it right? if yes, follow me.
1) x = 1 and x=0 are vertical asymptotes and during interval (0,1) this function is continuous
2) if x approaches to the 0+ y goes to the ∞ and when x approaches to the 1- then y goes to the -∞
3) if x = 1/2 y = 0 it means this function through of x-axis at (1/2,0)
4) on the other hand, this function at given interval is always decreasing because f'(x) = -1/(x-1)2 - 1/x2 as you see always is negative.
Result: this function has no any critical points and also y will be (-∞, ∞) so there is not any local or absolute maximum or minimum point.
I hope it is useful,
Minoo